shuf

generate random permutations

TLDR

Randomize the order of lines in a file and output the result

>_ shuf [filename]
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Only output the first 5 entries of the result

>_ shuf -n [5] [filename]
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Write the output to another file

>_ shuf [filename] -o [output_filename]
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Generate random numbers in range

>_ shuf -i [1-10]
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SYNOPSIS

shuf [ OPTION ]...[ FILE ]
shuf -e [ OPTION ]...[ ARG ]...
shuf -i LO-HI [ OPTION ]...

DESCRIPTION

Write a random permutation of the input lines to standard output.

With no FILE, or when FILE is -, read standard input.

Mandatory arguments to long options are mandatory for short options too.

-e , --echo treat each ARG as an input line

-i , --input -range = LO -HI treat each number LO through HI as an input line

-n , --head -count = COUNT output at most COUNT lines

-o , --output = FILE write result to FILE instead of standard output

--random -source = FILE get random bytes from FILE

-r , --repeat output lines can be repeated

-z , --zero -terminated line delimiter is NUL, not newline

--help display this help and exit

--version output version information and exit

REPORTING BUGS

GNU coreutils online help: <https://www.gnu.org/software/coreutils/>
Report any translation bugs to <https://translationproject.org/team/>

COPYRIGHT

Copyright 2019 Free Software Foundation, Inc. License GPLv3+: GNU GPL version 3 or later <https://gnu.org/licenses/gpl.html>.
This is free software: you are free to change and redistribute it. There is NO WARRANTY, to the extent permitted by law.

SEE ALSO

Full documentation <https://www.gnu.org/software/coreutils/shuf> or available locally via: info shuf invocation

AUTHOR

Written by Paul Eggert.

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