LinuxCommandLibrary

id

return user identity

TLDR

Display current user's ID (UID), group ID (GID) and groups to which they belong

$ id
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Display the current user identity as a number
$ id -u
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Display the current group identity as a number
$ id -g
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Display an arbitrary user's ID (UID), group ID (GID) and groups to which they belong
$ id [username]
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SYNOPSIS

id [OPTION]... [USER]...

DESCRIPTION

Print user and group information for each specified USER, or (when USER omitted) for the current process.

-a

ignore, for compatibility with other versions

-Z, --context

print only the security context of the process

-g, --group

print only the effective group ID

-G, --groups

print all group IDs

-n, --name

print a name instead of a number, for -ugG

-r, --real

print the real ID instead of the effective ID, with -ugG

-u, --user

print only the effective user ID

-z, --zero

delimit entries with NUL characters, not whitespace;

not permitted in default format

--help

display this help and exit

--version

output version information and exit

Without any OPTION, print some useful set of identified information.

REPORTING BUGS

GNU coreutils online help: <https://www.gnu.org/software/coreutils/>
Report any translation bugs to <https://translationproject.org/team/>

COPYRIGHT

Copyright © 2023 Free Software Foundation, Inc. License GPLv3+: GNU GPL version 3 or later <https://gnu.org/licenses/gpl.html>.
This is free software: you are free to change and redistribute it. There is NO WARRANTY, to the extent permitted by law.

SEE ALSO

Full documentation <https://www.gnu.org/software/coreutils/id> or available locally via: info '(coreutils) id invocation'

AUTHOR

Written by Arnold Robbins and David MacKenzie.

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